ProofCalculusIntroProof Builder

Proof that a differentiable function is continuous

This proof shows why differentiability is a stronger condition than continuity. The difference factors into a difference quotient times , and that product is forced to zero.

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Proof Builder makes the factorization argument easy to follow line by line. The proof is short, but each step matters: express the increment as a product, take limits, and then read continuity off the result.

The core idea

Continuity at means as . Differentiability gives exactly the right expression to study that difference.

For nonzero , you can factor the increment as . One factor tends to and the other tends to , so their product tends to .

Why this makes differentiability stronger

Continuity only asks that the function values meet up at the point. Differentiability asks for a stable local slope as well.

That extra slope information is what forces continuity automatically. The converse fails because an unbroken graph can still have a corner and therefore no derivative.

Common Pitfall

You cannot reverse this theorem. A function may be continuous at a point and still fail to be differentiable there, as happens for at .

Try a Variation

Apply the same increment argument to a constant function. What happens to the difference quotient, and how does the proof simplify?

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